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15-9a^2=-1885
We move all terms to the left:
15-9a^2-(-1885)=0
We add all the numbers together, and all the variables
-9a^2+1900=0
a = -9; b = 0; c = +1900;
Δ = b2-4ac
Δ = 02-4·(-9)·1900
Δ = 68400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{68400}=\sqrt{3600*19}=\sqrt{3600}*\sqrt{19}=60\sqrt{19}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{19}}{2*-9}=\frac{0-60\sqrt{19}}{-18} =-\frac{60\sqrt{19}}{-18} =-\frac{10\sqrt{19}}{-3} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{19}}{2*-9}=\frac{0+60\sqrt{19}}{-18} =\frac{60\sqrt{19}}{-18} =\frac{10\sqrt{19}}{-3} $
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